25y*y=3

Solution for 25y*y=3 equation:

25y*y=3

We move all terms to the left:

25y*y-(3)=0

Wy multiply elements

25y^2-3=0

a = 25; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·25·(-3)
Δ = 300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{300}=\sqrt{100*3}=\sqrt{100}*\sqrt{3}=10\sqrt{3}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{3}}{2*25}=\frac{0-10\sqrt{3}}{50}
=-\frac{10\sqrt{3}}{50}
=-\frac{\sqrt{3}}{5}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{3}}{2*25}=\frac{0+10\sqrt{3}}{50}
=\frac{10\sqrt{3}}{50}
=\frac{\sqrt{3}}{5}
$