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3x-x-5=2(x+2)-9.
We move all terms to the left:
3x-x-5-(2(x+2)-9.)=0
We add all the numbers together, and all the variables
2x-(2(x+2)-9.)-5=0
We calculate terms in parentheses: -(2(x+2)-9.), so:We get rid of parentheses
2(x+2)-9.
We add all the numbers together, and all the variables
2(x+2)-9
We multiply parentheses
2x+4-9
We add all the numbers together, and all the variables
2x-5
Back to the equation:
-(2x-5)
2x-2x+5-5=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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