4(8-4n)=2(n-40)+4n

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Solution for 4(8-4n)=2(n-40)+4n equation: 



4(8-4n)=2(n-40)+4n

We move all terms to the left:

4(8-4n)-(2(n-40)+4n)=0

We add all the numbers together, and all the variables

4(-4n+8)-(2(n-40)+4n)=0

We multiply parentheses

-16n-(2(n-40)+4n)+32=0



We calculate terms in parentheses: -(2(n-40)+4n), so:

2(n-40)+4n

We add all the numbers together, and all the variables

4n+2(n-40)

We multiply parentheses

4n+2n-80

We add all the numbers together, and all the variables

6n-80

Back to the equation:

-(6n-80)



We get rid of parentheses

-16n-6n+80+32=0

We add all the numbers together, and all the variables

-22n+112=0

We move all terms containing n to the left, all other terms to the right

-22n=-112

n=-112/-22

n=5+1/11

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