3x-9x+67=3x+40

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Solution for 3x-9x+67=3x+40 equation: 



3x-9x+67=3x+40

We move all terms to the left:

3x-9x+67-(3x+40)=0

We add all the numbers together, and all the variables

-6x-(3x+40)+67=0

We get rid of parentheses

-6x-3x-40+67=0

We add all the numbers together, and all the variables

-9x+27=0

We move all terms containing x to the left, all other terms to the right

-9x=-27

x=-27/-9

x=+3

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