40(2n-1)=5(14n+12)

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Solution for 40(2n-1)=5(14n+12) equation: 



40(2n-1)=5(14n+12)

We move all terms to the left:

40(2n-1)-(5(14n+12))=0

We multiply parentheses

80n-(5(14n+12))-40=0



We calculate terms in parentheses: -(5(14n+12)), so:

5(14n+12)

We multiply parentheses

70n+60

Back to the equation:

-(70n+60)



We get rid of parentheses

80n-70n-60-40=0

We add all the numbers together, and all the variables

10n-100=0

We move all terms containing n to the left, all other terms to the right

10n=100

n=100/10

n=10

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