3x-8=-3(x-4)+10

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Solution for 3x-8=-3(x-4)+10 equation: 



3x-8=-3(x-4)+10

We move all terms to the left:

3x-8-(-3(x-4)+10)=0



We calculate terms in parentheses: -(-3(x-4)+10), so:

-3(x-4)+10

We multiply parentheses

-3x+12+10

We add all the numbers together, and all the variables

-3x+22

Back to the equation:

-(-3x+22)



We get rid of parentheses

3x+3x-22-8=0

We add all the numbers together, and all the variables

6x-30=0

We move all terms containing x to the left, all other terms to the right

6x=30

x=30/6

x=5

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