4(3g+1)=28

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Solution for 4(3g+1)=28 equation: 



4(3g+1)=28

We move all terms to the left:

4(3g+1)-(28)=0

We multiply parentheses

12g+4-28=0

We add all the numbers together, and all the variables

12g-24=0

We move all terms containing g to the left, all other terms to the right

12g=24

g=24/12

g=2

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