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3x-8-x=2(x-4)
We move all terms to the left:
3x-8-x-(2(x-4))=0
We add all the numbers together, and all the variables
2x-(2(x-4))-8=0
We calculate terms in parentheses: -(2(x-4)), so:We get rid of parentheses
2(x-4)
We multiply parentheses
2x-8
Back to the equation:
-(2x-8)
2x-2x+8-8=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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