10-2(3x-3)=8-(5x+3)

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Solution for 10-2(3x-3)=8-(5x+3) equation: 



10-2(3x-3)=8-(5x+3)

We move all terms to the left:

10-2(3x-3)-(8-(5x+3))=0

We multiply parentheses

-6x-(8-(5x+3))+6+10=0



We calculate terms in parentheses: -(8-(5x+3)), so:

8-(5x+3)

determiningTheFunctionDomain
-(5x+3)+8

We get rid of parentheses

-5x-3+8

We add all the numbers together, and all the variables

-5x+5

Back to the equation:

-(-5x+5)



We add all the numbers together, and all the variables

-6x-(-5x+5)+16=0

We get rid of parentheses

-6x+5x-5+16=0

We add all the numbers together, and all the variables

-1x+11=0

We move all terms containing x to the left, all other terms to the right

-x=-11

x=-11/-1

x=+11

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