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3x-6(2x-3)=-2(x-1)+8
We move all terms to the left:
3x-6(2x-3)-(-2(x-1)+8)=0
We multiply parentheses
3x-12x-(-2(x-1)+8)+18=0
We calculate terms in parentheses: -(-2(x-1)+8), so:We add all the numbers together, and all the variables
-2(x-1)+8
We multiply parentheses
-2x+2+8
We add all the numbers together, and all the variables
-2x+10
Back to the equation:
-(-2x+10)
-9x-(-2x+10)+18=0
We get rid of parentheses
-9x+2x-10+18=0
We add all the numbers together, and all the variables
-7x+8=0
We move all terms containing x to the left, all other terms to the right
-7x=-8
x=-8/-7
x=1+1/7
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