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3x-5x(x-1)=3
We move all terms to the left:
3x-5x(x-1)-(3)=0
We multiply parentheses
-5x^2+3x+5x-3=0
We add all the numbers together, and all the variables
-5x^2+8x-3=0
a = -5; b = 8; c = -3;
Δ = b2-4ac
Δ = 82-4·(-5)·(-3)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2}{2*-5}=\frac{-10}{-10} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2}{2*-5}=\frac{-6}{-10} =3/5 $
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