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3x-5=6-(2x+1)
We move all terms to the left:
3x-5-(6-(2x+1))=0
We calculate terms in parentheses: -(6-(2x+1)), so:We get rid of parentheses
6-(2x+1)
determiningTheFunctionDomain -(2x+1)+6
We get rid of parentheses
-2x-1+6
We add all the numbers together, and all the variables
-2x+5
Back to the equation:
-(-2x+5)
3x+2x-5-5=0
We add all the numbers together, and all the variables
5x-10=0
We move all terms containing x to the left, all other terms to the right
5x=10
x=10/5
x=2
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