x+x+2+2(x+2)-2=20

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Solution for x+x+2+2(x+2)-2=20 equation: 



x+x+2+2(x+2)-2=20

We move all terms to the left:

x+x+2+2(x+2)-2-(20)=0

We add all the numbers together, and all the variables

2x+2(x+2)-20=0

We multiply parentheses

2x+2x+4-20=0

We add all the numbers together, and all the variables

4x-16=0

We move all terms containing x to the left, all other terms to the right

4x=16

x=16/4

x=4

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