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3x-5=(5x-3)/x
We move all terms to the left:
3x-5-((5x-3)/x)=0
Domain of the equation: x)!=0We multiply all the terms by the denominator
x!=0/1
x!=0
x∈R
3x*x)-((5x-3)-5*x)=0
Wy multiply elements
3x^2-5x=0
a = 3; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·3·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*3}=\frac{0}{6} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*3}=\frac{10}{6} =1+2/3 $
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