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3x-5+2=-3(1-x)
We move all terms to the left:
3x-5+2-(-3(1-x))=0
We add all the numbers together, and all the variables
3x-(-3(-1x+1))-5+2=0
We add all the numbers together, and all the variables
3x-(-3(-1x+1))-3=0
We calculate terms in parentheses: -(-3(-1x+1)), so:We get rid of parentheses
-3(-1x+1)
We multiply parentheses
3x-3
Back to the equation:
-(3x-3)
3x-3x+3-3=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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