3x-4=19+x+10

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Solution for 3x-4=19+x+10 equation: 



3x-4=19+x+10

We move all terms to the left:

3x-4-(19+x+10)=0

We add all the numbers together, and all the variables

3x-(x+29)-4=0

We get rid of parentheses

3x-x-29-4=0

We add all the numbers together, and all the variables

2x-33=0

We move all terms containing x to the left, all other terms to the right

2x=33

x=33/2

x=16+1/2

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