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3(x-5)+2=2(5+x)
We move all terms to the left:
3(x-5)+2-(2(5+x))=0
We add all the numbers together, and all the variables
3(x-5)-(2(x+5))+2=0
We multiply parentheses
3x-(2(x+5))-15+2=0
We calculate terms in parentheses: -(2(x+5)), so:We add all the numbers together, and all the variables
2(x+5)
We multiply parentheses
2x+10
Back to the equation:
-(2x+10)
3x-(2x+10)-13=0
We get rid of parentheses
3x-2x-10-13=0
We add all the numbers together, and all the variables
x-23=0
We move all terms containing x to the left, all other terms to the right
x=23
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