14x2+11x+3=2x2-3x+3

Solution for 14x2+11x+3=2x2-3x+3 equation:

14x^2+11x+3=2x^2-3x+3

We move all terms to the left:

14x^2+11x+3-(2x^2-3x+3)=0

We get rid of parentheses

14x^2-2x^2+11x+3x-3+3=0

We add all the numbers together, and all the variables

12x^2+14x=0

a = 12; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·12·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*12}=\frac{-28}{24}
=-1+1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*12}=\frac{0}{24}
=0
$