-2-(m-5)=1-(m-2)

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Solution for -2-(m-5)=1-(m-2) equation: 



-2-(m-5)=1-(m-2)

We move all terms to the left:

-2-(m-5)-(1-(m-2))=0

We get rid of parentheses

-m-(1-(m-2))+5-2=0



We calculate terms in parentheses: -(1-(m-2)), so:

1-(m-2)

determiningTheFunctionDomain
-(m-2)+1

We get rid of parentheses

-m+2+1

We add all the numbers together, and all the variables

-1m+3

Back to the equation:

-(-1m+3)



We add all the numbers together, and all the variables

-1m-(-1m+3)+3=0

We get rid of parentheses

-1m+1m-3+3=0

We add all the numbers together, and all the variables

=0

m=0/1

m=0

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