3x-4(3x-5)=2(3x-4)-2

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Solution for 3x-4(3x-5)=2(3x-4)-2 equation: 



3x-4(3x-5)=2(3x-4)-2

We move all terms to the left:

3x-4(3x-5)-(2(3x-4)-2)=0

We multiply parentheses

3x-12x-(2(3x-4)-2)+20=0



We calculate terms in parentheses: -(2(3x-4)-2), so:

2(3x-4)-2

We multiply parentheses

6x-8-2

We add all the numbers together, and all the variables

6x-10

Back to the equation:

-(6x-10)



We add all the numbers together, and all the variables

-9x-(6x-10)+20=0

We get rid of parentheses

-9x-6x+10+20=0

We add all the numbers together, and all the variables

-15x+30=0

We move all terms containing x to the left, all other terms to the right

-15x=-30

x=-30/-15

x=+2

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