38-4(n-2)+5n=-20+25(1-n)-6n

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Solution for 38-4(n-2)+5n=-20+25(1-n)-6n equation: 



38-4(n-2)+5n=-20+25(1-n)-6n

We move all terms to the left:

38-4(n-2)+5n-(-20+25(1-n)-6n)=0

We add all the numbers together, and all the variables

-4(n-2)+5n-(-20+25(-1n+1)-6n)+38=0

We add all the numbers together, and all the variables

5n-4(n-2)-(-20+25(-1n+1)-6n)+38=0

We multiply parentheses

5n-4n-(-20+25(-1n+1)-6n)+8+38=0



We calculate terms in parentheses: -(-20+25(-1n+1)-6n), so:

-20+25(-1n+1)-6n

determiningTheFunctionDomain
25(-1n+1)-6n-20

We add all the numbers together, and all the variables

-6n+25(-1n+1)-20

We multiply parentheses

-6n-25n+25-20

We add all the numbers together, and all the variables

-31n+5

Back to the equation:

-(-31n+5)



We add all the numbers together, and all the variables

n-(-31n+5)+46=0

We get rid of parentheses

n+31n-5+46=0

We add all the numbers together, and all the variables

32n+41=0

We move all terms containing n to the left, all other terms to the right

32n=-41

n=-41/32

n=-1+9/32

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