3x-4(1-2x)=8-(4x-3)

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Solution for 3x-4(1-2x)=8-(4x-3) equation: 



3x-4(1-2x)=8-(4x-3)

We move all terms to the left:

3x-4(1-2x)-(8-(4x-3))=0

We add all the numbers together, and all the variables

3x-4(-2x+1)-(8-(4x-3))=0

We multiply parentheses

3x+8x-(8-(4x-3))-4=0



We calculate terms in parentheses: -(8-(4x-3)), so:

8-(4x-3)

determiningTheFunctionDomain
-(4x-3)+8

We get rid of parentheses

-4x+3+8

We add all the numbers together, and all the variables

-4x+11

Back to the equation:

-(-4x+11)



We add all the numbers together, and all the variables

11x-(-4x+11)-4=0

We get rid of parentheses

11x+4x-11-4=0

We add all the numbers together, and all the variables

15x-15=0

We move all terms containing x to the left, all other terms to the right

15x=15

x=15/15

x=1

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