3(x+1)=4+2(x-1)

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Solution for 3(x+1)=4+2(x-1) equation: 



3(x+1)=4+2(x-1)

We move all terms to the left:

3(x+1)-(4+2(x-1))=0

We multiply parentheses

3x-(4+2(x-1))+3=0



We calculate terms in parentheses: -(4+2(x-1)), so:

4+2(x-1)

determiningTheFunctionDomain
2(x-1)+4

We multiply parentheses

2x-2+4

We add all the numbers together, and all the variables

2x+2

Back to the equation:

-(2x+2)



We get rid of parentheses

3x-2x-2+3=0

We add all the numbers together, and all the variables

x+1=0

We move all terms containing x to the left, all other terms to the right

x=-1

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