3x-3x=-4(2-5x)-5(4x-4)

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Solution for 3x-3x=-4(2-5x)-5(4x-4) equation: 



3x-3x=-4(2-5x)-5(4x-4)

We move all terms to the left:

3x-3x-(-4(2-5x)-5(4x-4))=0

We add all the numbers together, and all the variables

3x-3x-(-4(-5x+2)-5(4x-4))=0

We add all the numbers together, and all the variables

-(-4(-5x+2)-5(4x-4))=0



We calculate terms in parentheses: -(-4(-5x+2)-5(4x-4)), so:

-4(-5x+2)-5(4x-4)

We multiply parentheses

20x-20x-8+20

We add all the numbers together, and all the variables

12

Back to the equation:

-(12)



We move all terms containing x to the left, all other terms to the right

=12

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