(10(3)+32)+(20(3)+2)+(7y+6)=360

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Solution for (10(3)+32)+(20(3)+2)+(7y+6)=360 equation: 



(10(3)+32)+(20(3)+2)+(7y+6)=360

We move all terms to the left:

(10(3)+32)+(20(3)+2)+(7y+6)-(360)=0

determiningTheFunctionDomain
(7y+6)-360+(103+32)+(203+2)=0

We add all the numbers together, and all the variables

(7y+6)-360+135+205=0

We add all the numbers together, and all the variables

(7y+6)-20=0

We get rid of parentheses

7y+6-20=0

We add all the numbers together, and all the variables

7y-14=0

We move all terms containing y to the left, all other terms to the right

7y=14

y=14/7

y=2

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