3x-38=5(2x-2)

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Solution for 3x-38=5(2x-2) equation: 



3x-38=5(2x-2)

We move all terms to the left:

3x-38-(5(2x-2))=0



We calculate terms in parentheses: -(5(2x-2)), so:

5(2x-2)

We multiply parentheses

10x-10

Back to the equation:

-(10x-10)



We get rid of parentheses

3x-10x+10-38=0

We add all the numbers together, and all the variables

-7x-28=0

We move all terms containing x to the left, all other terms to the right

-7x=28

x=28/-7

x=-4

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