5(x-2)=4x+27

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Solution for 5(x-2)=4x+27 equation: 



5(x-2)=4x+27

We move all terms to the left:

5(x-2)-(4x+27)=0

We multiply parentheses

5x-(4x+27)-10=0

We get rid of parentheses

5x-4x-27-10=0

We add all the numbers together, and all the variables

x-37=0

We move all terms containing x to the left, all other terms to the right

x=37

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