3x-3(4-3x)=3(x-3)-39

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Solution for 3x-3(4-3x)=3(x-3)-39 equation: 



3x-3(4-3x)=3(x-3)-39

We move all terms to the left:

3x-3(4-3x)-(3(x-3)-39)=0

We add all the numbers together, and all the variables

3x-3(-3x+4)-(3(x-3)-39)=0

We multiply parentheses

3x+9x-(3(x-3)-39)-12=0



We calculate terms in parentheses: -(3(x-3)-39), so:

3(x-3)-39

We multiply parentheses

3x-9-39

We add all the numbers together, and all the variables

3x-48

Back to the equation:

-(3x-48)



We add all the numbers together, and all the variables

12x-(3x-48)-12=0

We get rid of parentheses

12x-3x+48-12=0

We add all the numbers together, and all the variables

9x+36=0

We move all terms containing x to the left, all other terms to the right

9x=-36

x=-36/9

x=-4

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