3x-21(2x-5)=2(X+3)-8

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Solution for 3x-21(2x-5)=2(X+3)-8 equation: 



3x-21(2x-5)=2(x+3)-8

We move all terms to the left:

3x-21(2x-5)-(2(x+3)-8)=0

We multiply parentheses

3x-42x-(2(x+3)-8)+105=0



We calculate terms in parentheses: -(2(x+3)-8), so:

2(x+3)-8

We multiply parentheses

2x+6-8

We add all the numbers together, and all the variables

2x-2

Back to the equation:

-(2x-2)



We add all the numbers together, and all the variables

-39x-(2x-2)+105=0

We get rid of parentheses

-39x-2x+2+105=0

We add all the numbers together, and all the variables

-41x+107=0

We move all terms containing x to the left, all other terms to the right

-41x=-107

x=-107/-41

x=2+25/41

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