3x-2(2x-5)=2(x+3)+8

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Solution for 3x-2(2x-5)=2(x+3)+8 equation: 



3x-2(2x-5)=2(x+3)+8

We move all terms to the left:

3x-2(2x-5)-(2(x+3)+8)=0

We multiply parentheses

3x-4x-(2(x+3)+8)+10=0



We calculate terms in parentheses: -(2(x+3)+8), so:

2(x+3)+8

We multiply parentheses

2x+6+8

We add all the numbers together, and all the variables

2x+14

Back to the equation:

-(2x+14)



We add all the numbers together, and all the variables

-1x-(2x+14)+10=0

We get rid of parentheses

-1x-2x-14+10=0

We add all the numbers together, and all the variables

-3x-4=0

We move all terms containing x to the left, all other terms to the right

-3x=4

x=4/-3

x=-1+1/3

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