3x-1x(x+2)=2(x+2)

Solution for 3x-1x(x+2)=2(x+2) equation:

3x-1x(x+2)=2(x+2)

We move all terms to the left:

3x-1x(x+2)-(2(x+2))=0

We multiply parentheses

-x^2+3x-2x-(2(x+2))=0


We calculate terms in parentheses: -(2(x+2)), so:

2(x+2)

We multiply parentheses

2x+4

Back to the equation:

-(2x+4)


We add all the numbers together, and all the variables

-1x^2+x-(2x+4)=0

We get rid of parentheses

-1x^2+x-2x-4=0

We add all the numbers together, and all the variables

-1x^2-1x-4=0

a = -1; b = -1; c = -4;
Δ = b2-4ac
Δ = -12-4·(-1)·(-4)
Δ = -15
Delta is less than zero, so there is no solution for the equation