5(x-3)-1/2(4x-6)=8-x+4x-2+6x

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Solution for 5(x-3)-1/2(4x-6)=8-x+4x-2+6x equation: 



5(x-3)-1/2(4x-6)=8-x+4x-2+6x

We move all terms to the left:

5(x-3)-1/2(4x-6)-(8-x+4x-2+6x)=0



Domain of the equation: 2(4x-6)!=0

x∈R



We add all the numbers together, and all the variables

5(x-3)-1/2(4x-6)-(9x+6)=0

We multiply parentheses

5x-1/2(4x-6)-(9x+6)-15=0

We get rid of parentheses

5x-1/2(4x-6)-9x-6-15=0

We multiply all the terms by the denominator


5x*2(4x-6)-9x*2(4x-6)-6*2(4x-6)-15*2(4x-6)-1=0

Wy multiply elements

10x^2(4-18x^2(4-12x(4-30x(4-1=0

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