3x-1=8(x+1)+

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Solution for 3x-1=8(x+1)+ equation: 



3x-1=8(x+1)+

We move all terms to the left:

3x-1-(8(x+1)+)=0



We calculate terms in parentheses: -(8(x+1)+), so:

8(x+1)+

We add all the numbers together, and all the variables

8(x+1)

We multiply parentheses

8x+8

Back to the equation:

-(8x+8)



We get rid of parentheses

3x-8x-8-1=0

We add all the numbers together, and all the variables

-5x-9=0

We move all terms containing x to the left, all other terms to the right

-5x=9

x=9/-5

x=-1+4/5

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