(2z+1)=(6z-9)

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Solution for (2z+1)=(6z-9) equation: 



(2z+1)=(6z-9)

We move all terms to the left:

(2z+1)-((6z-9))=0

We get rid of parentheses

2z-((6z-9))+1=0



We calculate terms in parentheses: -((6z-9)), so:

(6z-9)

We get rid of parentheses

6z-9

Back to the equation:

-(6z-9)



We get rid of parentheses

2z-6z+9+1=0

We add all the numbers together, and all the variables

-4z+10=0

We move all terms containing z to the left, all other terms to the right

-4z=-10

z=-10/-4

z=2+1/2

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