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3x-16/8x-14=0
Domain of the equation: 8x!=0We multiply all the terms by the denominator
x!=0/8
x!=0
x∈R
3x*8x-14*8x-16=0
Wy multiply elements
24x^2-112x-16=0
a = 24; b = -112; c = -16;
Δ = b2-4ac
Δ = -1122-4·24·(-16)
Δ = 14080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14080}=\sqrt{256*55}=\sqrt{256}*\sqrt{55}=16\sqrt{55}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-112)-16\sqrt{55}}{2*24}=\frac{112-16\sqrt{55}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-112)+16\sqrt{55}}{2*24}=\frac{112+16\sqrt{55}}{48} $
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