200=5/2(25+b)

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Solution for 200=5/2(25+b) equation: 



200=5/2(25+b)

We move all terms to the left:

200-(5/2(25+b))=0



Domain of the equation: 2(25+b))!=0

b∈R



We add all the numbers together, and all the variables

-(5/2(b+25))+200=0

We multiply all the terms by the denominator


-(5+200*2(b+25))=0



We calculate terms in parentheses: -(5+200*2(b+25)), so:

5+200*2(b+25)

determiningTheFunctionDomain
200*2(b+25)+5

Wy multiply elements

400b(b+5

Back to the equation:

-(400b(b+5)





We calculate terms in parentheses: -(400b(b+5), so:

400b(b+5





We calculate terms in parentheses: -(400b(b+5), so:

400b(b+5





We calculate terms in parentheses: -(400b(b+5), so:

400b(b+5





We calculate terms in parentheses: -(400b(b+5), so:

400b(b+5





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400b(b+5





We calculate terms in parentheses: -(400b(b+5), so:

400b(b+5





We calculate terms in parentheses: -(400b(b+5), so:

400b(b+5





We calculate terms in parentheses: -(400b(b+5), so:

400b(b+5





We calculate terms in parentheses: -(400b(b+5), so:

400b(b+5





We calculate terms in parentheses: -(400b(b+5), so:

400b(b+5





We calculate terms in parentheses: -(400b(b+5), so:

400b(b+5





We calculate terms in parentheses: -(400b(b+5), so:

400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





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400b(b+5





We calculate terms in parentheses: -(400b(b+5), so:

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