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3x-15=1/2x+5
We move all terms to the left:
3x-15-(1/2x+5)=0
Domain of the equation: 2x+5)!=0We get rid of parentheses
x∈R
3x-1/2x-5-15=0
We multiply all the terms by the denominator
3x*2x-5*2x-15*2x-1=0
Wy multiply elements
6x^2-10x-30x-1=0
We add all the numbers together, and all the variables
6x^2-40x-1=0
a = 6; b = -40; c = -1;
Δ = b2-4ac
Δ = -402-4·6·(-1)
Δ = 1624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1624}=\sqrt{4*406}=\sqrt{4}*\sqrt{406}=2\sqrt{406}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-2\sqrt{406}}{2*6}=\frac{40-2\sqrt{406}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+2\sqrt{406}}{2*6}=\frac{40+2\sqrt{406}}{12} $
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