3/2b+b+(b+45)+2b-90+90=540

Solution for 3/2b+b+(b+45)+2b-90+90=540 equation:

3/2b+b+(b+45)+2b-90+90=540

We move all terms to the left:

3/2b+b+(b+45)+2b-90+90-(540)=0


Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R


We add all the numbers together, and all the variables

3b+3/2b+(b+45)-540=0

We get rid of parentheses

3b+3/2b+b+45-540=0

We multiply all the terms by the denominator


3b*2b+b*2b+45*2b-540*2b+3=0

Wy multiply elements

6b^2+2b^2+90b-1080b+3=0

We add all the numbers together, and all the variables

8b^2-990b+3=0

a = 8; b = -990; c = +3;
Δ = b2-4ac
Δ = -9902-4·8·3
Δ = 980004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{980004}=\sqrt{4*245001}=\sqrt{4}*\sqrt{245001}=2\sqrt{245001}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-990)-2\sqrt{245001}}{2*8}=\frac{990-2\sqrt{245001}}{16}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-990)+2\sqrt{245001}}{2*8}=\frac{990+2\sqrt{245001}}{16}
$