3x-(x-2)+2(2+x)=4-2x-(x-3)

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Solution for 3x-(x-2)+2(2+x)=4-2x-(x-3) equation: 



3x-(x-2)+2(2+x)=4-2x-(x-3)

We move all terms to the left:

3x-(x-2)+2(2+x)-(4-2x-(x-3))=0

We add all the numbers together, and all the variables

3x-(x-2)+2(x+2)-(4-2x-(x-3))=0

We multiply parentheses

3x-(x-2)+2x-(4-2x-(x-3))+4=0

We get rid of parentheses

3x-x+2x-(4-2x-(x-3))+2+4=0



We calculate terms in parentheses: -(4-2x-(x-3)), so:

4-2x-(x-3)

determiningTheFunctionDomain
-2x-(x-3)+4

We get rid of parentheses

-2x-x+3+4

We add all the numbers together, and all the variables

-3x+7

Back to the equation:

-(-3x+7)



We add all the numbers together, and all the variables

4x-(-3x+7)+6=0

We get rid of parentheses

4x+3x-7+6=0

We add all the numbers together, and all the variables

7x-1=0

We move all terms containing x to the left, all other terms to the right

7x=1

x=1/7

x=1/7

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