3(x+2)-2(x+1)=4(3x-2)-2(2+x)

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Solution for 3(x+2)-2(x+1)=4(3x-2)-2(2+x) equation: 



3(x+2)-2(x+1)=4(3x-2)-2(2+x)

We move all terms to the left:

3(x+2)-2(x+1)-(4(3x-2)-2(2+x))=0

We add all the numbers together, and all the variables

3(x+2)-2(x+1)-(4(3x-2)-2(x+2))=0

We multiply parentheses

3x-2x-(4(3x-2)-2(x+2))+6-2=0



We calculate terms in parentheses: -(4(3x-2)-2(x+2)), so:

4(3x-2)-2(x+2)

We multiply parentheses

12x-2x-8-4

We add all the numbers together, and all the variables

10x-12

Back to the equation:

-(10x-12)



We add all the numbers together, and all the variables

x-(10x-12)+4=0

We get rid of parentheses

x-10x+12+4=0

We add all the numbers together, and all the variables

-9x+16=0

We move all terms containing x to the left, all other terms to the right

-9x=-16

x=-16/-9

x=1+7/9

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