3x-(x+3)+5=2(x+1)

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Solution for 3x-(x+3)+5=2(x+1) equation: 



3x-(x+3)+5=2(x+1)

We move all terms to the left:

3x-(x+3)+5-(2(x+1))=0

We get rid of parentheses

3x-x-(2(x+1))-3+5=0



We calculate terms in parentheses: -(2(x+1)), so:

2(x+1)

We multiply parentheses

2x+2

Back to the equation:

-(2x+2)



We add all the numbers together, and all the variables

2x-(2x+2)+2=0

We get rid of parentheses

2x-2x-2+2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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