2m+2(4m-5)=-2(10-4m)

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Solution for 2m+2(4m-5)=-2(10-4m) equation: 



2m+2(4m-5)=-2(10-4m)

We move all terms to the left:

2m+2(4m-5)-(-2(10-4m))=0

We add all the numbers together, and all the variables

2m+2(4m-5)-(-2(-4m+10))=0

We multiply parentheses

2m+8m-(-2(-4m+10))-10=0



We calculate terms in parentheses: -(-2(-4m+10)), so:

-2(-4m+10)

We multiply parentheses

8m-20

Back to the equation:

-(8m-20)



We add all the numbers together, and all the variables

10m-(8m-20)-10=0

We get rid of parentheses

10m-8m+20-10=0

We add all the numbers together, and all the variables

2m+10=0

We move all terms containing m to the left, all other terms to the right

2m=-10

m=-10/2

m=-5

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