3(x-6)+15=4(x+1)+4

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Solution for 3(x-6)+15=4(x+1)+4 equation: 



3(x-6)+15=4(x+1)+4

We move all terms to the left:

3(x-6)+15-(4(x+1)+4)=0

We multiply parentheses

3x-(4(x+1)+4)-18+15=0



We calculate terms in parentheses: -(4(x+1)+4), so:

4(x+1)+4

We multiply parentheses

4x+4+4

We add all the numbers together, and all the variables

4x+8

Back to the equation:

-(4x+8)



We add all the numbers together, and all the variables

3x-(4x+8)-3=0

We get rid of parentheses

3x-4x-8-3=0

We add all the numbers together, and all the variables

-1x-11=0

We move all terms containing x to the left, all other terms to the right

-x=11

x=11/-1

x=-11

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