3x-(8-2x)=7x-2(x+4)

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Solution for 3x-(8-2x)=7x-2(x+4) equation: 



3x-(8-2x)=7x-2(x+4)

We move all terms to the left:

3x-(8-2x)-(7x-2(x+4))=0

We add all the numbers together, and all the variables

3x-(-2x+8)-(7x-2(x+4))=0

We get rid of parentheses

3x+2x-(7x-2(x+4))-8=0



We calculate terms in parentheses: -(7x-2(x+4)), so:

7x-2(x+4)

We multiply parentheses

7x-2x-8

We add all the numbers together, and all the variables

5x-8

Back to the equation:

-(5x-8)



We add all the numbers together, and all the variables

5x-(5x-8)-8=0

We get rid of parentheses

5x-5x+8-8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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