2(t-3)-3(3t-1)=3-5(4t+5)

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Solution for 2(t-3)-3(3t-1)=3-5(4t+5) equation: 



2(t-3)-3(3t-1)=3-5(4t+5)

We move all terms to the left:

2(t-3)-3(3t-1)-(3-5(4t+5))=0

We multiply parentheses

2t-9t-(3-5(4t+5))-6+3=0



We calculate terms in parentheses: -(3-5(4t+5)), so:

3-5(4t+5)

determiningTheFunctionDomain
-5(4t+5)+3

We multiply parentheses

-20t-25+3

We add all the numbers together, and all the variables

-20t-22

Back to the equation:

-(-20t-22)



We add all the numbers together, and all the variables

-7t-(-20t-22)-3=0

We get rid of parentheses

-7t+20t+22-3=0

We add all the numbers together, and all the variables

13t+19=0

We move all terms containing t to the left, all other terms to the right

13t=-19

t=-19/13

t=-1+6/13

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