3x-(8+12x)-(7+4x)=6x-(3-8x)+13

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Solution for 3x-(8+12x)-(7+4x)=6x-(3-8x)+13 equation: 



3x-(8+12x)-(7+4x)=6x-(3-8x)+13

We move all terms to the left:

3x-(8+12x)-(7+4x)-(6x-(3-8x)+13)=0

We add all the numbers together, and all the variables

3x-(12x+8)-(4x+7)-(6x-(-8x+3)+13)=0

We get rid of parentheses

3x-12x-4x-(6x-(-8x+3)+13)-8-7=0



We calculate terms in parentheses: -(6x-(-8x+3)+13), so:

6x-(-8x+3)+13

We get rid of parentheses

6x+8x-3+13

We add all the numbers together, and all the variables

14x+10

Back to the equation:

-(14x+10)



We add all the numbers together, and all the variables

-13x-(14x+10)-15=0

We get rid of parentheses

-13x-14x-10-15=0

We add all the numbers together, and all the variables

-27x-25=0

We move all terms containing x to the left, all other terms to the right

-27x=25

x=25/-27

x=-25/27

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