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3x-(2x-5)=7+(3x-5)
We move all terms to the left:
3x-(2x-5)-(7+(3x-5))=0
We get rid of parentheses
3x-2x-(7+(3x-5))+5=0
We calculate terms in parentheses: -(7+(3x-5)), so:We add all the numbers together, and all the variables
7+(3x-5)
determiningTheFunctionDomain (3x-5)+7
We get rid of parentheses
3x-5+7
We add all the numbers together, and all the variables
3x+2
Back to the equation:
-(3x+2)
x-(3x+2)+5=0
We get rid of parentheses
x-3x-2+5=0
We add all the numbers together, and all the variables
-2x+3=0
We move all terms containing x to the left, all other terms to the right
-2x=-3
x=-3/-2
x=1+1/2
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