4(x-2)=(8x-3)-12

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Solution for 4(x-2)=(8x-3)-12 equation: 



4(x-2)=(8x-3)-12

We move all terms to the left:

4(x-2)-((8x-3)-12)=0

We multiply parentheses

4x-((8x-3)-12)-8=0



We calculate terms in parentheses: -((8x-3)-12), so:

(8x-3)-12

We get rid of parentheses

8x-3-12

We add all the numbers together, and all the variables

8x-15

Back to the equation:

-(8x-15)



We get rid of parentheses

4x-8x+15-8=0

We add all the numbers together, and all the variables

-4x+7=0

We move all terms containing x to the left, all other terms to the right

-4x=-7

x=-7/-4

x=1+3/4

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