3x-(12-8x)=3(x-10)+18

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Solution for 3x-(12-8x)=3(x-10)+18 equation: 



3x-(12-8x)=3(x-10)+18

We move all terms to the left:

3x-(12-8x)-(3(x-10)+18)=0

We add all the numbers together, and all the variables

3x-(-8x+12)-(3(x-10)+18)=0

We get rid of parentheses

3x+8x-(3(x-10)+18)-12=0



We calculate terms in parentheses: -(3(x-10)+18), so:

3(x-10)+18

We multiply parentheses

3x-30+18

We add all the numbers together, and all the variables

3x-12

Back to the equation:

-(3x-12)



We add all the numbers together, and all the variables

11x-(3x-12)-12=0

We get rid of parentheses

11x-3x+12-12=0

We add all the numbers together, and all the variables

8x=0

x=0/8

x=0

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