3x+x-2x+8=3x+x(-x)

Solution for 3x+x-2x+8=3x+x(-x) equation:

3x+x-2x+8=3x+x(-x)

We move all terms to the left:

3x+x-2x+8-(3x+x(-x))=0

We add all the numbers together, and all the variables

3x+x-2x-(3x+x(-1x))+8=0

We add all the numbers together, and all the variables

2x-(3x+x(-1x))+8=0


We calculate terms in parentheses: -(3x+x(-1x)), so:

3x+x(-1x)

We multiply parentheses

-1x^2+3x

Back to the equation:

-(-1x^2+3x)


We get rid of parentheses

1x^2-3x+2x+8=0

We add all the numbers together, and all the variables

x^2-1x+8=0

a = 1; b = -1; c = +8;
Δ = b2-4ac
Δ = -12-4·1·8
Δ = -31
Delta is less than zero, so there is no solution for the equation